Mathematical Analysis Zorich Solutions | Complete

whenever

Then, whenever |x - x0| < δ , we have

Using the inequality |1/x - 1/x0| = |x0 - x| / |xx0| ≤ |x0 - x| / x0^2 , we can choose δ = min(x0^2 ε, x0/2) . mathematical analysis zorich solutions

|1/x - 1/x0| < ε

def plot_function(): x = np.linspace(0.1, 10, 100) y = 1 / x whenever Then, whenever |x - x0| &lt; δ