Sqlite3 Tutorial Query Python Fixed «DELUXE – 2027»

import sqlite3

conn = sqlite3.connect('adventure.db') cursor = conn.cursor() As Pythonia ventured deeper into the forest, she encountered a wise old sage who taught her the ancient incantation of SELECT .

conn.close() The people of Codearia celebrated Pythonia's mastery of SQLite3, and her legendary adventures were etched into the annals of database history. For those who wish to relive Pythonia's adventures, here is the complete code: sqlite3 tutorial query python fixed

# UPDATE cursor.execute('UPDATE characters SET health = 100 WHERE name = "Pythonia"') conn.commit()

# Close the connection conn.close()

cursor.execute(''' CREATE TABLE IF NOT EXISTS inventory ( item TEXT, quantity INTEGER ) ''')

cursor.execute('SELECT * FROM inventory WHERE quantity > 0') rows = cursor.fetchall() for row in rows: print(row) The wise old sage appeared once more, explaining that the WHERE clause was used to filter data based on conditions. In this case, Pythonia was retrieving only the rows where the quantity column was greater than 0. A fierce dragon, known as the UPDATE beast, guarded the treasure of modified data. Pythonia, armed with her trusty UPDATE statement, charged into battle. import sqlite3 conn = sqlite3

# Create a connection to the database conn = sqlite3.connect('adventure.db') cursor = conn.cursor()